Waec Model Questions Vol1 2019 Geography Question 45

Practice objective / multiple choice question 45 from the 2019 Waec Model Questions Vol1 Geography examination.

Waec Model Questions Vol1 2019 Geography Objective / Multiple Choice Hard Difficulty
Question 45 WAEC_MODEL_QUESTIONS_VOL1 • 2019 • GEOGRAPHY • objective

A farmer has 10 ha of land for maize. Each plant needs 0.25 m² for optimal yield. The fertilizer cost per hectare (in ₦) decreases with planting density D (thousands of plants per ha) according to Cost = 5000 - 200 D. Yield per plant (tonnes) is 0.8 t when D ≤ 4, but when D > 4 it falls linearly: Yield = 0.8 - 0.05 (D - 4). The market price is ₦1500 per tonne. Profit = (total yield × price) - (total fertilizer cost for 10 ha). Determine the planting density (in plants per ha, nearest whole plant) that maximises profit.

Answer Options

A. 9 000 plants per ha
Correct Answer B. 10 000 plants per ha
C. 12 000 plants per ha
D. 8 000 plants per ha
Correct Answer
B
Correct Option:
10 000 plants per ha

About This Question

This is Waec Model Questions Vol1 2019 Geography Question 45. It is one of the objective questions from the 2019 Waec Model Questions Vol1 Geography examination.

Difficulty level: Hard .

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