Neco Model Questions Vol1 2018 Chemistry Question 29

Practice objective / multiple choice question 29 from the 2018 Neco Model Questions Vol1 Chemistry examination.

Neco Model Questions Vol1 2018 Chemistry Objective / Multiple Choice Medium Difficulty
Question 29 NECO_MODEL_QUESTIONS_VOL1 • 2018 • CHEMISTRY • objective

The normal boiling point of a solvent at 1 atm is \(78.0^{\circ}\text{C}\). Dissolving a non‑volatile solute raises the boiling point to \(80.5^{\circ}\text{C}\). The solvent's molal boiling‑point elevation constant is \(K_b = 0.512^{\circ}\text{C·kg mol}^{-1}\). Assuming the solute does not dissociate and is glucose (\(M = 180.16\ \text{g mol}^{-1}\)), calculate (a) the molality of the solution and (b) the mass of glucose required when \(250.0\ \text{g}\) of solvent is used.

Answer Options

A. molality = 4.55 m; mass of glucose ≈ 2.10×10^2 g
Correct Answer B. molality = 4.88 m; mass of glucose ≈ 2.20×10^2 g
C. molality = 4.88 m; mass of glucose ≈ 2.05×10^2 g
D. molality = 5.12 m; mass of glucose ≈ 2.35×10^2 g
Correct Answer
B
Correct Option:
molality = 4.88 m; mass of glucose ≈ 2.20×10^2 g

About This Question

This is Neco Model Questions Vol1 2018 Chemistry Question 29. It is one of the objective questions from the 2018 Neco Model Questions Vol1 Chemistry examination.

Difficulty level: Medium .

Master the Exam!

You've seen a preview, but there are thousands more questions plus AI tutor to break down complex solutions.

Unlock Full Access Available for Android & Windows
Chat with Support