A mixture containing 10.0 g of ethanol ($\ce{C2H5OH}$, M = 46.07 g mol$^{-1}$) and 12.0 g of acetic acid ($\ce{CH3COOH}$, M = 60.05 g mol$^{-1}$) is heated with excess sulfuric acid catalyst to produce ethyl acetate ($\ce{CH3COOC2H5}$) and water according to $\ce{C2H5OH + CH3COOH - CH3COOC2H5 + H2O}$.\n(a) Identify the limiting reagent and calculate the theoretical mass of ethyl acetate formed.\n(b) If the isolated mass of ethyl acetate is 9.0 g, determine the percent yield.\n(c) The reaction mixture is then distilled and 0.10 mol of water is collected. Assuming all water originates from the esterification, calculate the mass of unreacted ethanol remaining in the mixture.

Question

A mixture containing 10.0 g of ethanol ($\ce{C2H5OH}$, M = 46.07 g mol$^{-1}$) and 12.0 g of acetic acid ($\ce{CH3COOH}$, M = 60.05 g mol$^{-1}$) is heated with excess sulfuric acid catalyst to produce ethyl acetate ($\ce{CH3COOC2H5}$) and water according to $\ce{C2H5OH + CH3COOH -> CH3COOC2H5 + H2O}$.\n(a) Identify the limiting reagent and calculate the theoretical mass of ethyl acetate formed.\n(b) If the isolated mass of ethyl acetate is 9.0 g, determine the percent yield.\n(c) The reaction mixture is then distilled and 0.10 mol of water is collected. Assuming all water originates from the esterification, calculate the mass of unreacted ethanol remaining in the mixture.

Accepted Answer

Limiting reagent: acetic acid; theoretical ethyl acetate = 17.6 g; percent yield ≈ 51 %; unreacted ethanol ≈ 5.39 g

Neco 2025 Chemistry Question 50

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