Neco 2024 Physics Question 41

Practice objective / multiple choice question 41 from the 2024 Neco Physics examination.

Neco 2024 Physics Objective / Multiple Choice Hard Difficulty
Question 41 NECO • 2024 • PHYSICS • objective

A rectangular coil of 50 turns has dimensions \(0.20\,\text{m}\) by \(0.10\,\text{m}\). It is placed in a uniform magnetic field of \(0.5\,\text{T}\) perpendicular to the plane of the coil. The coil is pulled out of the field so that the side of length \(0.20\,\text{m}\) remains parallel to the field lines and the coil moves at constant speed, leaving the field completely after \(0.40\,\text{s}\). \( (a) \) Determine the speed of the coil as it exits the field. \( (b) \) Calculate the average magnitude of the induced emf in the coil during this motion. \( (c) \) State the direction of the induced current as seen from the side where the magnetic field points towards you.

Answer Options

A. Speed = 0.20 m s⁻¹; average emf = 1.00 V; current direction = counter‑clockwise (as viewed from the side of the field).
B. Speed = 0.25 m s⁻¹; average emf = 1.25 V; current direction = counter‑clockwise (as viewed from the side of the field).
C. Speed = 0.30 m s⁻¹; average emf = 1.50 V; current direction = clockwise (as viewed from the side of the field).
Correct Answer D. Speed = 0.25 m s⁻¹; average emf = 1.25 V; current direction = clockwise (as viewed from the side of the field).
Correct Answer
D
Correct Option:
Speed = 0.25 m s⁻¹; average emf = 1.25 V; current direction = clockwise (as viewed from the side of the field).

About This Question

This is Neco 2024 Physics Question 41. It is one of the objective questions from the 2024 Neco Physics examination.

Difficulty level: Hard .

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