Question 40
NECO
•
2023
•
PHYSICS
•
objective
A converging lens of focal length \(f = 12\ \text{cm}\) forms a real image of a candle on a screen. The distance between the candle and the screen is fixed at 80 cm.\n\n(a) Find the possible distances of the lens from the candle.\n(b) For each position, calculate the magnification \(m\) and state whether the image is upright or inverted.\n(c) If the candle has a height of 5.0 cm, determine the height of the image for each case.
Answer Options
A.
Lens can be placed either 10.0 cm from the candle (image 70.0 cm away, magnification ≈ -7.00, image height ≈ 35.0 cm, inverted) or 70.0 cm from the candle (image 10.0 cm away, magnification ≈ -0.14, image height ≈ 0.7 cm, inverted).
Correct Answer
B.
Lens can be placed either 14.7 cm from the candle (image 65.3 cm away, magnification ≈ -4.44, image height ≈ 22.2 cm, inverted) or 65.3 cm from the candle (image 14.7 cm away, magnification ≈ -0.225, image height ≈ 1.1 cm, inverted).
C.
Lens can be placed either 30.0 cm from the candle (image 50.0 cm away, magnification ≈ -1.67, image height ≈ 8.3 cm, inverted) or 50.0 cm from the candle (image 30.0 cm away, magnification ≈ -0.60, image height ≈ 3.0 cm, inverted).
D.
Lens can be placed either 20.0 cm from the candle (image 60.0 cm away, magnification ≈ -3.00, image height ≈ 15.0 cm, inverted) or 60.0 cm from the candle (image 20.0 cm away, magnification ≈ -0.33, image height ≈ 1.7 cm, inverted).
Correct Answer
B
Correct Option:
Lens can be placed either 14.7 cm from the candle (image 65.3 cm away, magnification ≈ -4.44, image height ≈ 22.2 cm, inverted) or 65.3 cm from the candle (image 14.7 cm away, magnification ≈ -0.225, image height ≈ 1.1 cm, inverted).
About This Question
This is
Neco
2023
Physics
Question 40.
It is one of the
objective
questions from the
2023
Neco
Physics
examination.
Difficulty level:
Medium
.