Neco 2020 Physics Question 30

Practice objective / multiple choice question 30 from the 2020 Neco Physics examination.

Neco 2020 Physics Objective / Multiple Choice Hard Difficulty
Question 30 NECO • 2020 • PHYSICS • objective

A particle moves along a straight line with the velocity-time graph described below: \(\bullet\) From \(t=0\) to \(t=2\;\text{s}\), velocity increases uniformly from \(0\) to \(8\;\text{m s}^{-1}\). \(\bullet\) From \(t=2\) to \(t=5\;\text{s}\), velocity remains constant at \(8\;\text{m s}^{-1}\). \(\bullet\) From \(t=5\) to \(t=7\;\text{s}\), velocity decreases uniformly to \(-4\;\text{m s}^{-1}\). \(\bullet\) From \(t=7\) to \(t=9\;\text{s}\), velocity remains constant at \(-4\;\text{m s}^{-1}\). Determine (a) the total displacement of the particle over the 9 s interval, (b) the magnitude of its average speed, and (c) the instant at which the particle changes direction.

Answer Options

Correct Answer A. Displacement = 28 m; Average speed = 5.19 m s^{-1}; Direction change at t = 6.33 s
B. Displacement = 28 m; Average speed = 4.44 m s^{-1}; Direction change at t = 6.00 s
C. Displacement = 24 m; Average speed = 5.56 m s^{-1}; Direction change at t = 5.50 s
D. Displacement = 32 m; Average speed = 4.89 m s^{-1}; Direction change at t = 7.00 s
Correct Answer
A
Correct Option:
Displacement = 28 m; Average speed = 5.19 m s^{-1}; Direction change at t = 6.33 s

About This Question

This is Neco 2020 Physics Question 30. It is one of the objective questions from the 2020 Neco Physics examination.

Difficulty level: Hard .

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