Neco 2020 Chemistry Question 41

Practice objective / multiple choice question 41 from the 2020 Neco Chemistry examination.

Neco 2020 Chemistry Objective / Multiple Choice Hard Difficulty
Question 41 NECO • 2020 • CHEMISTRY • objective

A metal M forms the oxide \(\text{M}_2\text{O}_3\) with a standard enthalpy of formation \(\Delta H_f^\circ = -1200 \text{ kJ mol}^{-1}\). The oxide is reduced by carbon according to \(\text{M}_2\text{O}_3 + 3\text{C} \rightarrow 2\text{M} + 3\text{CO}\). The standard entropy change for the reaction is \(\Delta S^\circ = +200 \text{ J K}^{-1}\text{mol}^{-1}\). The standard enthalpy of formation of CO(g) is \(-110.5 \text{ kJ mol}^{-1}\). (a) Calculate the standard enthalpy change \(\Delta H^\circ\) for the reduction. (b) Determine the Gibbs free energy change \(\Delta G^\circ\) at \(1500 \text{ K}\) and state whether the reduction is spontaneous. (c) Find the minimum temperature at which the reduction becomes spontaneous (i.e., \(\Delta G^\circ =0\)).

Answer Options

Correct Answer A. ΔH° = +868.5 kJ mol⁻¹; ΔG°(1500 K) = +568.5 kJ mol⁻¹ (non‑spontaneous); Tmin ≈ 4.34×10³ K
B. ΔH° = -868.5 kJ mol⁻¹; ΔG°(1500 K) = -568.5 kJ mol⁻¹ (spontaneous); Tmin ≈ 2.5×10³ K
C. ΔH° = +868.5 kJ mol⁻¹; ΔG°(1500 K) = +300.0 kJ mol⁻¹ (non‑spontaneous); Tmin ≈ 3.00×10³ K
D. ΔH° = +1020.0 kJ mol⁻¹; ΔG°(1500 K) = +720.0 kJ mol⁻¹ (non‑spontaneous); Tmin ≈ 5.00×10³ K
Correct Answer
A
Correct Option:
ΔH° = +868.5 kJ mol⁻¹; ΔG°(1500 K) = +568.5 kJ mol⁻¹ (non‑spontaneous); Tmin ≈ 4.34×10³ K

About This Question

This is Neco 2020 Chemistry Question 41. It is one of the objective questions from the 2020 Neco Chemistry examination.

Difficulty level: Hard .

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