Neco 2019 Chemistry Question 40

Practice objective / multiple choice question 40 from the 2019 Neco Chemistry examination.

Neco 2019 Chemistry Objective / Multiple Choice Hard Difficulty
Question 40 NECO • 2019 • CHEMISTRY • objective

The esterification of acetic acid with ethanol is represented by\n\[\mathrm{CH_{3}COOH + C_{2}H_{5}OH \rightleftharpoons CH_{3}COOC_{2}H_{5} + H_{2}O}\]\nAt 25°C the equilibrium constant \(K_{c}\) is 4.0. Initially, 0.10 mol of each reactant are placed in a 1.00 L flask (no products present). (a) Determine the equilibrium concentrations of all four species. (b) If 0.05 mol of water are continuously removed from the system (the volume remains 1.00 L), calculate the new equilibrium concentration of ethyl acetate. (c) What is the percent increase in the amount of ethyl acetate formed relative to part (a)?

Answer Options

A. [HA]=[EtOH]=0.0400 M, [ester]=[H2O]=0.0600 M; new [ester]=0.0700 M; percent increase≈16.7 %
Correct Answer B. [HA]=[EtOH]=0.0333 M, [ester]=[H2O]=0.0667 M; new [ester]=0.0772 M; percent increase≈15.7 %
C. [HA]=[EtOH]=0.0250 M, [ester]=[H2O]=0.0750 M; new [ester]=0.0825 M; percent increase≈10.0 %
D. [HA]=[EtOH]=0.0300 M, [ester]=[H2O]=0.0700 M; new [ester]=0.0800 M; percent increase≈20.0 %
Correct Answer
B
Correct Option:
[HA]=[EtOH]=0.0333 M, [ester]=[H2O]=0.0667 M; new [ester]=0.0772 M; percent increase≈15.7 %

About This Question

This is Neco 2019 Chemistry Question 40. It is one of the objective questions from the 2019 Neco Chemistry examination.

Difficulty level: Hard .

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