Neco 2019 Chemistry Question 19

Practice objective / multiple choice question 19 from the 2019 Neco Chemistry examination.

Neco 2019 Chemistry Objective / Multiple Choice Medium Difficulty
Question 19 NECO • 2019 • CHEMISTRY • objective

A galvanic cell is constructed as \(\text{Zn}\,|\,\text{Zn}^{2+}(0.010\,\text{M})\,||\,\text{Cu}^{2+}(0.050\,\text{M})\,|\,\text{Cu}\) at 25\(^\circ\)C. Standard reduction potentials are \(E^{\circ}(\text{Zn}^{2+}+2e^{-}\rightarrow\text{Zn})=-0.76\,\text{V}\) and \(E^{\circ}(\text{Cu}^{2+}+2e^{-}\rightarrow\text{Cu})=+0.34\,\text{V}\). (a) Calculate the cell EMF under the given concentrations using the Nernst equation. (b) If the cell is allowed to run until \([\text{Cu}^{2+}] = 0.010\,\text{M}\) and \([\text{Zn}^{2+}] = 0.050\,\text{M}\), what is the new EMF? (c) Determine the maximum electrical work obtainable per mole of Zn oxidised under the initial conditions.

Answer Options

A. (a) 0.98\,\text{V}, (b) 0.95\,\text{V}, (c) 1.80\times10^{5}\,\text{J\,mol}^{-1} (≈180\,\text{kJ\,mol}^{-1})
B. (a) 1.20\,\text{V}, (b) 1.15\,\text{V}, (c) 2.30\times10^{5}\,\text{J\,mol}^{-1} (≈230\,\text{kJ\,mol}^{-1})
Correct Answer C. (a) 1.12\,\text{V}, (b) 1.08\,\text{V}, (c) 2.16\times10^{5}\,\text{J\,mol}^{-1} (≈216\,\text{kJ\,mol}^{-1})
D. (a) 1.05\,\text{V}, (b) 1.02\,\text{V}, (c) 2.00\times10^{5}\,\text{J\,mol}^{-1} (≈200\,\text{kJ\,mol}^{-1})
Correct Answer
C
Correct Option:
(a) 1.12\,\text{V}, (b) 1.08\,\text{V}, (c) 2.16\times10^{5}\,\text{J\,mol}^{-1} (≈216\,\text{kJ\,mol}^{-1})

About This Question

This is Neco 2019 Chemistry Question 19. It is one of the objective questions from the 2019 Neco Chemistry examination.

Difficulty level: Medium .

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