Neco 2019 Chemistry Question 14

Practice objective / multiple choice question 14 from the 2019 Neco Chemistry examination.

Neco 2019 Chemistry Objective / Multiple Choice Medium Difficulty
Question 14 NECO • 2019 • CHEMISTRY • objective

The lattice energy of an ionic compound can be approximated by \( U = k \dfrac{z^+ z^-}{r} \), where \( k \) is a constant, \( z^+ \) and \( z^- \) are the charges on the cation and anion, and \( r \) is the inter‑ionic distance (in pm). For \( \text{ACl} \) (where \( z^+ = 1, z^- = 1 \)) the measured lattice energy is 750 kJ·mol⁻¹ and \( r = 260 \) pm. Assuming the same constant \( k \) applies, calculate the lattice energy of \( \text{BCl}_2 \) (where \( z^+ = 2, z^- = 1 \) and \( r = 210 \) pm). Comment on the relative solubility of \( \text{BCl}_2 \) in water compared with \( \text{ACl} \).

Answer Options

A. ≈ 2 500 kJ·mol⁻¹ (and BCl₂ is less soluble than ACl)
Correct Answer B. ≈ 1 860 kJ·mol⁻¹ (and BCl₂ is less soluble than ACl)
C. ≈ 1 200 kJ·mol⁻¹ (and BCl₂ is less soluble than ACl)
D. ≈ 1 860 kJ·mol⁻¹ (and BCl₂ is more soluble than ACl)
Correct Answer
B
Correct Option:
≈ 1 860 kJ·mol⁻¹ (and BCl₂ is less soluble than ACl)

About This Question

This is Neco 2019 Chemistry Question 14. It is one of the objective questions from the 2019 Neco Chemistry examination.

Difficulty level: Medium .

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