Neco 2019 Biology Question 44

Practice objective / multiple choice question 44 from the 2019 Neco Biology examination.

Neco 2019 Biology Objective / Multiple Choice Medium Difficulty
Question 44 NECO • 2019 • BIOLOGY • objective

A subject's plasma creatinine concentration is 0.9 mg dL-1, urine creatinine concentration is 120 mg dL-1 and urine flow rate is 1.2 mL min-1. Calculate the creatinine clearance in mL min-1. In the same subject, plasma PAH concentration is 0.02 mg mL-1, urine PAH concentration is 12 mg mL-1 and urine flow rate remains 1.2 mL min-1. Assuming the extraction ratio for PAH is 0.9 and that PAH clearance equals the effective renal plasma flow, estimate the true renal plasma flow (RPF) in mL min-1.

Answer Options

Correct Answer A. Creatinine clearance = 160 mL/min; RPF ≈ 800 mL/min
B. Creatinine clearance = 160 mL\/min; RPF ≈ 720 mL\/min
C. Creatinine clearance = 1600 mL\/min; RPF ≈ 720 mL\/min
D. Creatinine clearance = 1.6 mL\/min; RPF ≈ 800 mL\/min
Correct Answer
A
Correct Option:
Creatinine clearance = 160 mL/min; RPF ≈ 800 mL/min

About This Question

This is Neco 2019 Biology Question 44. It is one of the objective questions from the 2019 Neco Biology examination.

Difficulty level: Medium .

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