Neco 2018 Chemistry Question 36

Practice objective / multiple choice question 36 from the 2018 Neco Chemistry examination.

Neco 2018 Chemistry Objective / Multiple Choice Medium Difficulty
Question 36 NECO • 2018 • CHEMISTRY • objective

Consider the redox reaction that occurs in acidic solution where permanganate ion is reduced to manganese(II) ion and ferrous ion is oxidized to ferric ion. The half‑reaction for reduction is \(\ce{MnO4^- + 8H+ + 5e- -> Mn^{2+} + 4H2O}\) with \(E^\circ = +1.51\ \text{V}\). The half‑reaction for oxidation (as a reduction) is \(\ce{Fe^{3+} + e- -> Fe^{2+}}\) with \(E^\circ = +0.77\ \text{V}\). (a) Write the balanced overall redox equation. (b) Calculate the standard cell potential \(E^\circ_{\text{cell}}\) and state whether the reaction is spontaneous under standard conditions. (c) If 10.0 g of \(\ce{Fe^{2+}}\) are completely oxidised, determine the mass of \(\ce{KMnO4}\) required.

Answer Options

A. Balanced equation: \(\ce{MnO4^- + 8H+ + Fe^{2+} -> Mn^{2+} + 4H2O + Fe^{3+}}\); \(E^\circ_{\text{cell}} = 0.74\ \text{V}\) (spontaneous); mass of \(\ce{KMnO4}\) = 5.66 g.
B. Balanced equation: \(\ce{MnO4^- + 8H+ + 5Fe^{2+} -> Mn^{2+} + 4H2O + 5Fe^{3+}}\); \(E^\circ_{\text{cell}} = 0.78\ \text{V}\) (spontaneous); mass of \(\ce{KMnO4}\) = 5.66 g.
C. Balanced equation: \(\ce{MnO4^- + 8H+ + 5Fe^{2+} -> Mn^{2+} + 4H2O + 5Fe^{3+}}\); \(E^\circ_{\text{cell}} = 0.74\ \text{V}\) (spontaneous); mass of \(\ce{KMnO4}\) = 6.12 g.
Correct Answer D. Balanced equation: \(\ce{MnO4^- + 8H+ + 5Fe^{2+} -> Mn^{2+} + 4H2O + 5Fe^{3+}}\); \(E^\circ_{\text{cell}} = 0.74\ \text{V}\) (spontaneous); mass of \(\ce{KMnO4}\) = 5.66 g.
Correct Answer
D
Correct Option:
Balanced equation: \(\ce{MnO4^- + 8H+ + 5Fe^{2+} -> Mn^{2+} + 4H2O + 5Fe^{3+}}\); \(E^\circ_{\text{cell}} = 0.74\ \text{V}\) (spontaneous); mass of \(\ce{KMnO4}\) = 5.66 g.

About This Question

This is Neco 2018 Chemistry Question 36. It is one of the objective questions from the 2018 Neco Chemistry examination.

Difficulty level: Medium .

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