A galvanic cell is constructed with the half‑cells Fe^{3+}/Fe^{2+} (E° = +0.77 V) and Cu^{2+}/Cu (E° = +0.34 V). The concentrations are [Fe^{3+}] = 0.010 M, [Fe^{2+}] = 0.10 M and [Cu^{2+}] = 0.050 M at 298 K. Determine the cell EMF and state which electrode is the cathode.

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0.41 V, Fe^{3+}/Fe^{2+} (cathode)

Neco 2017 Chemistry Question 37

A galvanic cell is constructed with the half‑cells Fe^{3+}/Fe^{2+} (E° = +0.77 V) and Cu^{2+}/Cu (E° = +0.34 V). The concentrations are [Fe^{3+}] = 0.010 M, [Fe^{2+}] = 0.10 M and [Cu^{2+}] = 0.050 M at 298 K. Determine the cell EMF and state which electrode is the cathode.

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Neco 2017 Chemistry Question 37

A galvanic cell is constructed with the half‑cells Fe^{3+}/Fe^{2+} (E° = +0.77 V) and Cu^{2+}/Cu (E° = +0.34 V). The concentrations are [Fe^{3+}] = 0.010 M, [Fe^{2+}] = 0.10 M and [Cu^{2+}] = 0.050 M at 298 K. Determine the cell EMF and state which electrode is the cathode.

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Master the Exam!

A galvanic cell is constructed with the half‑cells Fe^{3+}/Fe^{2+} (E° = +0.77 V) and Cu^{2+}/Cu (E° = +0.34 V). The concentrations are [Fe^{3+}] = 0.010 M, [Fe^{2+}] = 0.10 M and [Cu^{2+}] = 0.050 M at 298 K. Determine the cell EMF and state which electrode is the cathode.