Igcse Model Questions Vol1 2025 Chemistry Question 18

Practice objective / multiple choice question 18 from the 2025 Igcse Model Questions Vol1 Chemistry examination.

Igcse Model Questions Vol1 2025 Chemistry Objective / Multiple Choice Hard Difficulty
Question 18 IGCSE_MODEL_QUESTIONS_VOL1 • 2025 • CHEMISTRY • objective

Propanoic acid (\(\mathrm{CH_3CH_2COOH}\)) reacts with ethanol (\(\mathrm{CH_3CH_2OH}\)) in an acid‑catalysed esterification: \(\mathrm{CH_3CH_2COOH + CH_3CH_2OH \rightleftharpoons CH_3CH_2COOCH_2CH_3 + H_2O}\). Initially, 0.050 mol of propanoic acid and 0.030 mol of ethanol are mixed, and the equilibrium constant at 25 °C is \(K = 4.0\) (based on concentrations). Calculate the amount (in moles, to three significant figures) of ethyl propanoate formed at equilibrium.

Answer Options

A. 0.0125 mol (≈1.3 g) of ethyl propanoate.
B. 0.0180 mol (≈1.9 g) of ethyl propanoate.
C. 0.0300 mol (≈3.1 g) of ethyl propanoate.
Correct Answer D. 0.0243 mol (≈2.5 g) of ethyl propanoate.
Correct Answer
D
Correct Option:
0.0243 mol (≈2.5 g) of ethyl propanoate.

About This Question

This is Igcse Model Questions Vol1 2025 Chemistry Question 18. It is one of the objective questions from the 2025 Igcse Model Questions Vol1 Chemistry examination.

Difficulty level: Hard .

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