Igcse Model Questions Vol1 2025 Biology Question 30

Practice objective / multiple choice question 30 from the 2025 Igcse Model Questions Vol1 Biology examination.

Igcse Model Questions Vol1 2025 Biology Objective / Multiple Choice Hard Difficulty
Question 30 IGCSE_MODEL_QUESTIONS_VOL1 • 2025 • BIOLOGY • objective

A 45‑year‑old patient has a fasting plasma glucose concentration of \(6.2\) mmol L\(^{-1}\) and a fasting insulin concentration of \(12\) µU mL\(^{-1}\). (a) Calculate the HOMA‑IR index using \(\text{HOMA‑IR}=\frac{\text{Glucose}\times\text{Insulin}}{22.5}\). (b) A lifestyle programme is expected to reduce the patient's body weight by 5 %, which in turn is estimated to lower fasting insulin by 15 % while glucose remains unchanged. Re‑calculate the HOMA‑IR after the programme and state whether the patient remains insulin‑resistant, using a threshold of HOMA‑IR > 2.5.

Answer Options

Correct Answer A. Initial HOMA‑IR ≈ 3.31 (insulin‑resistant). After 5 % weight loss, HOMA‑IR ≈ 2.81, still > 2.5, so the patient remains insulin‑resistant.
B. Initial HOMA‑IR ≈ 3.31 (insulin‑resistant). After 5 % weight loss, HOMA‑IR ≈ 2.81, which is ≤ 2.5, so the patient is no longer insulin‑resistant.
C. Initial HOMA‑IR ≈ 3.31 (insulin‑resistant). After 5 % weight loss, HOMA‑IR ≈ 2.95, still > 2.5, so the patient remains insulin‑resistant.
D. Initial HOMA‑IR ≈ 3.31 (insulin‑resistant). After 5 % weight loss, HOMA‑IR ≈ 2.30, which is ≤ 2.5, indicating the patient is no longer insulin‑resistant.
Correct Answer
A
Correct Option:
Initial HOMA‑IR ≈ 3.31 (insulin‑resistant). After 5 % weight loss, HOMA‑IR ≈ 2.81, still > 2.5, so the patient remains insulin‑resistant.

About This Question

This is Igcse Model Questions Vol1 2025 Biology Question 30. It is one of the objective questions from the 2025 Igcse Model Questions Vol1 Biology examination.

Difficulty level: Hard .

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