Gce Model Questions Vol1 2024 Chemistry Question 49
Practice objective / multiple choice question 49 from the 2024 Gce Model Questions Vol1 Chemistry examination.
A copolymer of styrene (M₁) and methyl methacrylate (M₂) is prepared. The monomer feed mole fraction of styrene is \(f_1=0.60\). The reactivity ratios are \(r_1=0.8\) for styrene and \(r_2=0.4\) for methyl methacrylate. Using the Mayo-Lewis equation, calculate the instantaneous mole fraction of styrene in the copolymer (\(F_1\)). Assuming the instantaneous composition remains constant throughout the reaction, give the overall mole fraction of styrene in the polymer after 50 % conversion.
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This is Gce Model Questions Vol1 2024 Chemistry Question 49. It is one of the objective questions from the 2024 Gce Model Questions Vol1 Chemistry examination.
Difficulty level: Hard .
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