Gce Model Questions Vol1 2023 Physics Question 4

Practice objective / multiple choice question 4 from the 2023 Gce Model Questions Vol1 Physics examination.

Gce Model Questions Vol1 2023 Physics Objective / Multiple Choice Hard Difficulty
Question 4 GCE_MODEL_QUESTIONS_VOL1 • 2023 • PHYSICS • objective

In the circuit shown, a 12 V ideal battery is connected in series with a 4 Ω resistor \(R_{1}\). The junction after \(R_{1}\) splits into a parallel network consisting of a 6 Ω resistor \(R_{2}\) and a load resistor \(R_{L}\). (i) Find the value of \(R_{L}\) that will receive maximum power and calculate that maximum power. (ii) If the battery has an internal resistance of 2 Ω (in series with the 12 V source), repeat the calculation: find the new value of \(R_{L}\) for maximum power transfer and the corresponding maximum power. Give all powers in watts to two decimal places.

Answer Options

A. (i) \(R_{L}=10\ \Omega\), \(P_{max}=1.00\ \text{W}\). (ii) With 2 Ω internal resistance: \(R_{L}=12\ \Omega\), \(P_{max}=0.60\ \text{W}\).
B. (i) \(R_{L}=8\ \Omega\), \(P_{max}=1.10\ \text{W}\). (ii) With 2 Ω internal resistance: \(R_{L}=10\ \Omega\), \(P_{max}=0.65\ \text{W}\).
Correct Answer C. (i) \(R_{L}=10\ \Omega\), \(P_{max}=1.30\ \text{W}\). (ii) With 2 Ω internal resistance: \(R_{L}=12\ \Omega\), \(P_{max}=0.75\ \text{W}\).
D. (i) \(R_{L}=12\ \Omega\), \(P_{max}=1.50\ \text{W}\). (ii) With 2 Ω internal resistance: \(R_{L}=14\ \Omega\), \(P_{max}=0.80\ \text{W}\).
Correct Answer
C
Correct Option:
(i) \(R_{L}=10\ \Omega\), \(P_{max}=1.30\ \text{W}\). (ii) With 2 Ω internal resistance: \(R_{L}=12\ \Omega\), \(P_{max}=0.75\ \text{W}\).

About This Question

This is Gce Model Questions Vol1 2023 Physics Question 4. It is one of the objective questions from the 2023 Gce Model Questions Vol1 Physics examination.

Difficulty level: Hard .

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