Gce Model Questions Vol1 2023 Chemistry Question 29

Practice objective / multiple choice question 29 from the 2023 Gce Model Questions Vol1 Chemistry examination.

Gce Model Questions Vol1 2023 Chemistry Objective / Multiple Choice Medium Difficulty

Question 29 GCE_MODEL_QUESTIONS_VOL1 • 2023 • CHEMISTRY • objective

A 0.0250 mol sample of the diprotic acid \(\mathrm{H_2A}\) (\(K_{a1}=1.0\times10^{-3}\), \(K_{a2}=1.0\times10^{-8}\)) is dissolved in 1.00 L of water. Titration is performed with 0.100 M NaOH solution. Calculate the volume of NaOH required to reach a pH of 8.00.

Answer Options

A. 400 mL

Correct Answer B. 375 mL

C. 425 mL

D. 350 mL

Correct Answer

Correct Option:

375 mL

About This Question

This is Gce Model Questions Vol1 2023 Chemistry Question 29. It is one of the objective questions from the 2023 Gce Model Questions Vol1 Chemistry examination.

Difficulty level: Medium .

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Gce Model Questions Vol1 2023 Chemistry Question 29

A 0.0250 mol sample of the diprotic acid \(\mathrm{H_2A}\) (\(K_{a1}=1.0\times10^{-3}\), \(K_{a2}=1.0\times10^{-8}\)) is dissolved in 1.00 L of water. Titration is performed with 0.100 M NaOH solution. Calculate the volume of NaOH required to reach a pH of 8.00.

Answer Options

About This Question

Master the Exam!

A 0.0250 mol sample of the diprotic acid \(\mathrm{H_2A}\) (\(K_{a1}=1.0\times10^{-3}\), \(K_{a2}=1.0\times10^{-8}\)) is dissolved in 1.00 L of water. Titration is performed with 0.100 M NaOH solution. Calculate the volume of NaOH required to reach a pH of 8.00.