Gce Model Questions Vol1 2022 Physics Question 27

Practice objective / multiple choice question 27 from the 2022 Gce Model Questions Vol1 Physics examination.

Gce Model Questions Vol1 2022 Physics Objective / Multiple Choice Hard Difficulty
Question 27 GCE_MODEL_QUESTIONS_VOL1 • 2022 • PHYSICS • objective

A uniformly charged rod of length L carries a linear charge density \(\lambda\) and lies along the x‑axis centred at the origin (from \(-L/2\) to \(+L/2\)). A point P is located a distance a above the centre of the rod on the perpendicular bisector. (a) Derive an expression for the magnitude of the electric field at P due to the rod. (b) A second identical rod is placed parallel to the first at a horizontal separation d (the rods are coplanar). Find the net electric field magnitude at the midpoint between the two rods. (c) If a uniform external electric field \(E_{\text{ext}}\) is applied opposite to the net field found in part (b), determine the magnitude of \(E_{\text{ext}}\) required to make the total electric field at that midpoint zero. Express your answer in terms of \(\lambda, L, a\) and \(\varepsilon_{0}\).

Answer Options

A. E_{ext}=\frac{\lambda L}{\pi\varepsilon_{0} a\sqrt{a^{2}+(L/2)^{2}}}
B. E_{ext}=\frac{\lambda L}{2\pi\varepsilon_{0} a\sqrt{a^{2}+L^{2}}}
C. E_{ext}=\frac{\lambda}{2\pi\varepsilon_{0} a\sqrt{a^{2}+(L/2)^{2}}}
Correct Answer D. E_{ext}=\frac{\lambda L}{2\pi\varepsilon_{0} a\sqrt{a^{2}+(L/2)^{2}}}
Correct Answer
D
Correct Option:
E_{ext}=\frac{\lambda L}{2\pi\varepsilon_{0} a\sqrt{a^{2}+(L/2)^{2}}}

About This Question

This is Gce Model Questions Vol1 2022 Physics Question 27. It is one of the objective questions from the 2022 Gce Model Questions Vol1 Physics examination.

Difficulty level: Hard .

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