Gce Model Questions Vol1 2021 Agricultural Science Question 4

Practice objective / multiple choice question 4 from the 2021 Gce Model Questions Vol1 Agricultural Science examination.

Gce Model Questions Vol1 2021 Agricultural Science Objective / Multiple Choice Hard Difficulty
Question 4 GCE_MODEL_QUESTIONS_VOL1 • 2021 • AGRICULTURAL_SCIENCE • objective

Cassava chips have an initial moisture content of 45 % (wet basis). The desired final moisture content is 12 % (wet basis). Drying follows the model \(M(t)=M_f+(M_0-M_f)e^{-kt}\) where \(M(t)\) is moisture content at time \(t\) (hours), \(M_0\) is the initial moisture content, \(M_f\) is the equilibrium moisture content (assumed 10 % wet basis), and \(k\) is the drying constant. In a trial, after 3 hours the moisture content measured is 20 % (wet basis). Determine the drying constant \(k\) (to three decimal places) and then calculate the total drying time required to reach the target 12 % moisture content. Give the time rounded to one decimal place (hours).

Answer Options

A. k = 0.500 h⁻¹; drying time ≈ 6.0 h
B. k = 0.418 h⁻¹; drying time ≈ 5.5 h
Correct Answer C. k = 0.418 h⁻¹; drying time ≈ 6.9 h
D. k = 0.350 h⁻¹; drying time ≈ 7.5 h
Correct Answer
C
Correct Option:
k = 0.418 h⁻¹; drying time ≈ 6.9 h

About This Question

This is Gce Model Questions Vol1 2021 Agricultural Science Question 4. It is one of the objective questions from the 2021 Gce Model Questions Vol1 Agricultural Science examination.

Difficulty level: Hard .

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