Gce Model Questions Vol1 2020 Physics Question 46

Practice objective / multiple choice question 46 from the 2020 Gce Model Questions Vol1 Physics examination.

Gce Model Questions Vol1 2020 Physics Objective / Multiple Choice Hard Difficulty
Question 46 GCE_MODEL_QUESTIONS_VOL1 • 2020 • PHYSICS • objective

A rectangular conducting loop of width \(0.10\ \text{m}\) and length \(0.30\ \text{m}\) has a resistance of \(2.0\ \Omega\). It is initially placed completely inside a uniform magnetic field of magnitude \(0.50\ \text{T}\) directed into the page. The loop is pulled out of the field at a constant speed \(v\), so that during the extraction a steady induced emf of \(0.15\ \text{V}\) is measured. (i) Determine the speed \(v\) of the loop. (ii) Calculate the rate at which electrical energy is converted into heat in the resistor, and state the mechanical power that must be supplied to keep the motion at constant speed.

Answer Options

A. v = 6.0\\ \text{m s}^{-1},\\ \text{power} = 4.5\\times10^{-2}\\ \text{W}
B. v = 1.5\\ \text{m s}^{-1},\\ \text{power} = 5.6\\times10^{-3}\\ \text{W}
Correct Answer C. v = 3.0\ \text{m s}^{-1},\ \text{power} = 1.13\times10^{-2}\ \text{W}
D. v = 2.0\\ \text{m s}^{-1},\\ \text{power} = 2.0\\times10^{-2}\\ \text{W}
Correct Answer
C
Correct Option:
v = 3.0\ \text{m s}^{-1},\ \text{power} = 1.13\times10^{-2}\ \text{W}

About This Question

This is Gce Model Questions Vol1 2020 Physics Question 46. It is one of the objective questions from the 2020 Gce Model Questions Vol1 Physics examination.

Difficulty level: Hard .

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