Gce Model Questions Vol1 2019 Physics Question 21
Practice objective / multiple choice question 21 from the 2019 Gce Model Questions Vol1 Physics examination.
A ^{226}_{88}Ra nucleus decays by emitting an \(\alpha\) particle to form ^{222}_{86}Rn, which subsequently undergoes a \(\beta^{+}\) decay to ^{222}_{85}At while emitting a positron. The atomic masses are: \(m(^{226}_{88}\text{Ra}) = 226.02541\ \text{u}\), \(m(^{222}_{86}\text{Rn}) = 222.01758\ \text{u}\), \(m(^{222}_{85}\text{At}) = 222.01850\ \text{u}\), \(m_{\alpha}=4.002603\ \text{u}\), and the positron mass \(m_{e^{+}} = 0.00054858\ \text{u}\). Using \(1\ \text{u}=931.5\ \text{MeV}\), calculate the total energy released in the combined decay sequence.
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This is Gce Model Questions Vol1 2019 Physics Question 21. It is one of the objective questions from the 2019 Gce Model Questions Vol1 Physics examination.
Difficulty level: Hard .
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