Gce Model Questions Vol1 2019 Chemistry Question 8

Practice objective / multiple choice question 8 from the 2019 Gce Model Questions Vol1 Chemistry examination.

Gce Model Questions Vol1 2019 Chemistry Objective / Multiple Choice Medium Difficulty

Question 8 GCE_MODEL_QUESTIONS_VOL1 • 2019 • CHEMISTRY • objective

A 0.250 M solution of the diprotic acid H₂A (\(K_{a1}=1.0\times10^{-3}\), \(K_{a2}=1.0\times10^{-8}\)) is titrated with 0.100 M NaOH. If 12.5 mL of NaOH is added to 25.0 mL of the acid solution, calculate the pH of the resulting solution.

Answer Options

Correct Answer A. 2.40

B. 2.70

C. 2.10

D. 3.00

Correct Answer

Correct Option:

2.40

About This Question

This is Gce Model Questions Vol1 2019 Chemistry Question 8. It is one of the objective questions from the 2019 Gce Model Questions Vol1 Chemistry examination.

Difficulty level: Medium .

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Gce Model Questions Vol1 2019 Chemistry Question 8

A 0.250 M solution of the diprotic acid H₂A (\(K_{a1}=1.0\times10^{-3}\), \(K_{a2}=1.0\times10^{-8}\)) is titrated with 0.100 M NaOH. If 12.5 mL of NaOH is added to 25.0 mL of the acid solution, calculate the pH of the resulting solution.

Answer Options

About This Question

Master the Exam!

A 0.250 M solution of the diprotic acid H₂A (\(K_{a1}=1.0\times10^{-3}\), \(K_{a2}=1.0\times10^{-8}\)) is titrated with 0.100 M NaOH. If 12.5 mL of NaOH is added to 25.0 mL of the acid solution, calculate the pH of the resulting solution.