Gce Model Questions Vol1 2019 Chemistry Question 3

Practice objective / multiple choice question 3 from the 2019 Gce Model Questions Vol1 Chemistry examination.

Gce Model Questions Vol1 2019 Chemistry Objective / Multiple Choice Medium Difficulty
Question 3 GCE_MODEL_QUESTIONS_VOL1 • 2019 • CHEMISTRY • objective

The molecule \(\mathrm{SF_2Cl_2}\) can exist as a cis isomer (the two F atoms adjacent) and a trans isomer (the two F atoms opposite). Both have a central S atom surrounded by four bonding pairs and two lone pairs. (a) State the hybridisation of the central S atom and give the approximate S-F bond angle in the cis isomer. (b) Which isomer possesses the larger dipole moment and why?

Answer Options

A. Hybridisation: sp³d²; S-F angle ≈ 180°. Trans isomer has the larger dipole moment.
B. Hybridisation: sp³d; S-F angle ≈ 120°. Trans isomer has the larger dipole moment.
Correct Answer C. Hybridisation: sp³d²; S-F angle ≈ 90°. Cis isomer has the larger dipole moment.
D. Hybridisation: sp³; S-F angle ≈ 109.5°. Cis isomer has the larger dipole moment.
Correct Answer
C
Correct Option:
Hybridisation: sp³d²; S-F angle ≈ 90°. Cis isomer has the larger dipole moment.

About This Question

This is Gce Model Questions Vol1 2019 Chemistry Question 3. It is one of the objective questions from the 2019 Gce Model Questions Vol1 Chemistry examination.

Difficulty level: Medium .

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