Gce Model Questions Vol1 2019 Agricultural Science Question 34
Practice objective / multiple choice question 34 from the 2019 Gce Model Questions Vol1 Agricultural Science examination.
Cassava chips are dried in a solar dryer. Their moisture content follows \( M(t)= (M_0-M_{eq})e^{-kt}+M_{eq} \) where \(M_0=45\%\) (wet basis), equilibrium moisture \(M_{eq}=10\%\) and drying constant \(k=0.15\ \text{day}^{-1}\). Drying is stopped when the moisture reaches 15 %, after which the chips are stored in a silo that loses moisture at a constant rate of 0.2 % per day due to respiration. How many total days (drying plus storage) are required for the chips to reach a safe moisture content of 12 %?
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About This Question
This is Gce Model Questions Vol1 2019 Agricultural Science Question 34. It is one of the objective questions from the 2019 Gce Model Questions Vol1 Agricultural Science examination.
Difficulty level: Hard .
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