Gce Model Questions Vol1 2018 Agricultural Science Question 5

Practice objective / multiple choice question 5 from the 2018 Gce Model Questions Vol1 Agricultural Science examination.

Gce Model Questions Vol1 2018 Agricultural Science Objective / Multiple Choice Medium Difficulty
Question 5 GCE_MODEL_QUESTIONS_VOL1 • 2018 • AGRICULTURAL_SCIENCE • objective

A farmer targets 8 t ha\(^{-1}\) of maize. Soil tests show available N = 60 kg ha\(^{-1}\), P = 20 kg ha\(^{-1}\), K = 30 kg ha\(^{-1}\). Crop removal rates are 20 kg N t\(^{-1}\), 5 kg P t\(^{-1}\), 15 kg K t\(^{-1}\). Fertiliser sources are urea (46 % N), DAP (18 % N, 46 % P\(_2\)O\(_5\)), and MOP (60 % K\(_2\)O). Convert P\(_2\)O\(_5\) to P (multiply by 0.44) and K\(_2\)O to K (multiply by 0.83). Calculate the required amounts of urea, DAP and MOP (kg ha\(^{-1}\)) to meet the nutrient deficits (round to the nearest kilogram).

Answer Options

Correct Answer A. Urea ≈ 179 kg ha⁻¹, DAP ≈ 99 kg ha⁻¹, MOP ≈ 181 kg ha⁻¹
B. Urea ≈ 165 kg ha⁻¹, DAP ≈ 105 kg ha⁻¹, MOP ≈ 190 kg ha⁻¹
C. Urea ≈ 190 kg ha⁻¹, DAP ≈ 100 kg ha⁻¹, MOP ≈ 170 kg ha⁻¹
D. Urea ≈ 180 kg ha⁻¹, DAP ≈ 92 kg ha⁻¹, MOP ≈ 175 kg ha⁻¹
Correct Answer
A
Correct Option:
Urea ≈ 179 kg ha⁻¹, DAP ≈ 99 kg ha⁻¹, MOP ≈ 181 kg ha⁻¹

About This Question

This is Gce Model Questions Vol1 2018 Agricultural Science Question 5. It is one of the objective questions from the 2018 Gce Model Questions Vol1 Agricultural Science examination.

Difficulty level: Medium .

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