Gce Model Questions Vol1 2018 Agricultural Science Question 25

Practice objective / multiple choice question 25 from the 2018 Gce Model Questions Vol1 Agricultural Science examination.

Gce Model Questions Vol1 2018 Agricultural Science Objective / Multiple Choice Hard Difficulty
Question 25 GCE_MODEL_QUESTIONS_VOL1 • 2018 • AGRICULTURAL_SCIENCE • objective

Cassava chips are to be dried in a solar dryer. The chips start with a moisture content of 45% (wet basis) and a temperature of \(30^{\circ}\)C. The dryer maintains an ambient temperature of \(45^{\circ}\)C and provides a drying constant \(k = 0.08\ \text{h}^{-1}\) according to Newton's law for moisture ratio: \(MR = e^{-kt}\), where \(MR = \frac{M-M_{e}}{M_{0}-M_{e}}\). The equilibrium moisture content at \(45^{\circ}\)C is 10% (wet basis). The target moisture content is 12% (wet basis).\n(a) Calculate the drying time required to reach the target moisture content.\n(b) If each hour of drying evaporates 0.5 L of water, compute the total water loss.\n(c) The market price of dried chips is \(\text{₦}200\) per kg. Drying incurs a fixed energy cost of \(\text{₦}150\) per batch. Assuming the initial fresh weight is 1000 kg and the dry matter remains constant, determine the profit per kilogram of dried product.

Answer Options

Correct Answer A. Drying time ≈ 35.8 h; water loss ≈ 17.9 kg; profit ≈ ₦199.8 per kg
B. Drying time ≈ 30.5 h; water loss ≈ 15.3 kg; profit ≈ ₦201.2 per kg
C. Drying time ≈ 42.0 h; water loss ≈ 21.0 kg; profit ≈ ₦197.0 per kg
D. Drying time ≈ 38.7 h; water loss ≈ 19.4 kg; profit ≈ ₦199.0 per kg
Correct Answer
A
Correct Option:
Drying time ≈ 35.8 h; water loss ≈ 17.9 kg; profit ≈ ₦199.8 per kg

About This Question

This is Gce Model Questions Vol1 2018 Agricultural Science Question 25. It is one of the objective questions from the 2018 Gce Model Questions Vol1 Agricultural Science examination.

Difficulty level: Hard .

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