Gce Model Questions Vol1 2017 Agricultural Science Question 5

Practice objective / multiple choice question 5 from the 2017 Gce Model Questions Vol1 Agricultural Science examination.

Gce Model Questions Vol1 2017 Agricultural Science Objective / Multiple Choice Medium Difficulty
Question 5 GCE_MODEL_QUESTIONS_VOL1 • 2017 • AGRICULTURAL_SCIENCE • objective

A soil test shows available nutrients of N = 40 kg ha⁻¹, P₂O₅ = 20 kg ha⁻¹ and K₂O = 30 kg ha⁻¹. The target levels for optimal maize yield are N = 120 kg ha⁻¹, P₂O₅ = 60 kg ha⁻¹ and K₂O = 80 kg ha⁻¹. The farmer wishes to apply a single blended fertilizer containing urea (46 % N), triple superphosphate (46 % P₂O₅) and muriate of potash (60 % K₂O) in the weight ratio 3 : 2 : 1 (urea : TSP : MOP). Determine the maximum amount of this blended fertilizer (kg ha⁻¹) that can be applied without exceeding any of the three nutrient targets by more than 5 %. Identify the limiting nutrient and give the quantities of urea, TSP and MOP in the blend at this application rate.

Answer Options

Correct Answer A. Maximum blend ≈ 280 kg ha⁻¹; limiting nutrient = P₂O₅; urea ≈ 140 kg, TSP ≈ 93 kg, MOP ≈ 47 kg per hectare
B. Maximum blend ≈ 300 kg ha⁻¹; limiting nutrient = N; urea ≈ 150 kg, TSP ≈ 100 kg, MOP ≈ 50 kg per hectare
C. Maximum blend ≈ 250 kg ha⁻¹; limiting nutrient = K₂O; urea ≈ 125 kg, TSP ≈ 83 kg, MOP ≈ 42 kg per hectare
D. Maximum blend ≈ 260 kg ha⁻¹; limiting nutrient = P₂O₅; urea ≈ 130 kg, TSP ≈ 86 kg, MOP ≈ 44 kg per hectare
Correct Answer
A
Correct Option:
Maximum blend ≈ 280 kg ha⁻¹; limiting nutrient = P₂O₅; urea ≈ 140 kg, TSP ≈ 93 kg, MOP ≈ 47 kg per hectare

About This Question

This is Gce Model Questions Vol1 2017 Agricultural Science Question 5. It is one of the objective questions from the 2017 Gce Model Questions Vol1 Agricultural Science examination.

Difficulty level: Medium .

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