Utme 2022 Chemistry Question 15

Practice objective / multiple choice question 15 from the 2022 Utme Chemistry examination. This question covers Thermochemistry, Acid-Base Reactions .

Utme 2022 Chemistry Objective / Multiple Choice 3 Difficulty
Topics: Thermochemistry Acid-Base Reactions
Question 15 UTME • 2022 • CHEMISTRY • objective

In dilute solution the heat of the reaction \( 2 \mathrm{NaOH} + \mathrm{HCl} \rightarrow \mathrm{NaCl} + \mathrm{H}_{2} \mathrm{O} \) is -57.3 kJ. Therefore the heat of the reaction \( 2 \mathrm{NaOH} + \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Na}_{2} \mathrm{SO}_{4} + 2 \mathrm{H}_{2} \mathrm{O} \) is

Answer Options

A. +28.65 kJ
B. -28.65 kJ
C. +57.3 kJ
Correct Answer D. -114.6 kJ
Correct Answer
D
Correct Option:
-114.6 kJ

About This Question

This is Utme 2022 Chemistry Question 15. It is one of the objective questions from the 2022 Utme Chemistry examination.

The question covers Thermochemistry, Acid-Base Reactions .

Difficulty level: 3 .

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