Post Utme Ksu 2021 Mathematics Question 11

Practice objective / multiple choice question 11 from the 2021 Post Utme Ksu Mathematics examination.

Post Utme Ksu 2021 Mathematics Objective / Multiple Choice

Question 11 POST_UTME_KSU • 2021 • MATHEMATICS • objective

Find the area under the curve \(y = \frac{1}{2}x^2 + 3x - 2\) from \(x = 0\) to \(x = 4\).

Correct Answer A. \(\frac{1}{2} \cdot 4^3 + 3 \cdot 4^2 - 2 \cdot 4\\)

B. \(\frac{1}{2} \cdot 4^2 + 3 \cdot 4 - 2\\)

C. \(\frac{1}{2} \cdot 4^3 + 3 \cdot 4^2 - 2\\)

D. \(\frac{1}{2} \cdot 4^2 + 3 \cdot 4^3 - 2\\)

Correct Answer

Correct Option:

\(\frac{1}{2} \cdot 4^3 + 3 \cdot 4^2 - 2 \cdot 4\\)

This is Post Utme Ksu 2021 Mathematics Question 11. It is one of the objective questions from the 2021 Post Utme Ksu Mathematics examination.

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