Post Utme Igbinedion University 2023 Chemistry Question 12

Practice objective / multiple choice question 12 from the 2023 Post Utme Igbinedion University Chemistry examination.

Post Utme Igbinedion University 2023 Chemistry Objective / Multiple Choice
Question 12 POST_UTME_IGBINEDION_UNIVERSITY • 2023 • CHEMISTRY • objective

A 25.0 mL sample of 0.500 M HCl is titrated with 1.00 M NaOH. Calculate the volume of NaOH required to reach the equivalence point.

Answer Options

Correct Answer A. \( V_{NaOH} = \frac{M_{HCl} \times V_{HCl}}{M_{NaOH}} \)
B. \( V_{NaOH} = \frac{M_{NaOH} \times V_{HCl}}{M_{HCl}} \)
C. \( V_{NaOH} = \frac{M_{HCl} \times V_{HCl}}{M_{NaOH} - M_{HCl}} \)
D. \( V_{NaOH} = \frac{M_{NaOH} \times V_{HCl}}{M_{HCl} + M_{NaOH}} \)
Correct Answer
A
Correct Option:
\( V_{NaOH} = \frac{M_{HCl} \times V_{HCl}}{M_{NaOH}} \)

About This Question

This is Post Utme Igbinedion University 2023 Chemistry Question 12. It is one of the objective questions from the 2023 Post Utme Igbinedion University Chemistry examination.

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