Question 32
POST_UTME_ABU
•
2023
•
CHEMISTRY
•
objective
A sample of a polymer has a molecular weight of 50000 g/mol. If the polymer is composed of 80% by mass of carbon and 20% by mass of hydrogen, calculate the number of moles of carbon atoms in 1 g of the polymer.
Answer Options
Correct Answer
A.
\text{Number of moles of carbon} = \frac{80 \text{ g}}{12.01 \text{ g/mol}} \times \frac{1 \text{ mol}}{6.022 \times 10^{23} \text{ atoms}}
B.
\text{Number of moles of carbon} = \frac{80 \text{ g}}{12.01 \text{ g/mol}} \times \frac{1 \text{ mol}}{6.022 \times 10^{23} \text{ atoms}} \times \frac{1 \text{ atom}}{1 \text{ mol}}
C.
\text{Number of moles of carbon} = \frac{80 \text{ g}}{12.01 \text{ g/mol}} \times \frac{1 \text{ mol}}{6.022 \times 10^{23} \text{ atoms}} \times \frac{1 \text{ atom}}{1 \text{ mol}} \times \frac{1 \text{ mol}}{1 \text{ g}}
D.
\text{Number of moles of carbon} = \frac{80 \text{ g}}{12.01 \text{ g/mol}} \times \frac{1 \text{ mol}}{6.022 \times 10^{23} \text{ atoms}} \times \frac{1 \text{ atom}}{1 \text{ mol}} \times \frac{1 \text{ mol}}{1 \text{ g}} \times \frac{1 \text{ g}}{1 \text{ mol}}
Correct Answer
A
Correct Option:
\text{Number of moles of carbon} = \frac{80 \text{ g}}{12.01 \text{ g/mol}} \times \frac{1 \text{ mol}}{6.022 \times 10^{23} \text{ atoms}}
About This Question
This is
Post Utme Abu
2023
Chemistry
Question 32.
It is one of the
objective
questions from the
2023
Post Utme Abu
Chemistry
examination.