Waec Model Questions Vol1 2018 Chemistry Question 14

Practice objective / multiple choice question 14 from the 2018 Waec Model Questions Vol1 Chemistry examination.

Waec Model Questions Vol1 2018 Chemistry Objective / Multiple Choice Medium Difficulty
Question 14 WAEC_MODEL_QUESTIONS_VOL1 • 2018 • CHEMISTRY • objective

In acidic solution the following half‑reactions have standard potentials:\n\nMnO₄⁻ + 8 H⁺ + 5 e⁻ → Mn²⁺ + 4 H₂O  E° = +1.51 V\nFe³⁺ + e⁻ → Fe²⁺  E° = +0.77 V\n\n(a) Write the balanced overall redox equation for the reaction between MnO₄⁻ and Fe²⁺.\n(b) Calculate the standard cell potential (E°cell).\n(c) Identify the oxidising agent and the reducing agent.

Answer Options

A. MnO4- + 8H+ + 5Fe2+ -> Mn2+ + 4H2O + 5Fe3+; E°cell = -0.74 V; oxidising agent = MnO4-; reducing agent = Fe2+
Correct Answer B. MnO4- + 8H+ + 5Fe2+ -> Mn2+ + 4H2O + 5Fe3+; E°cell = +0.74 V; oxidising agent = MnO4-; reducing agent = Fe2+
C. MnO4- + 8H+ + 5Fe2+ -> Mn2+ + 4H2O + 5Fe3+; E°cell = +0.68 V; oxidising agent = MnO4-; reducing agent = Fe2+
D. MnO4- + 8H+ + 5Fe2+ -> Mn2+ + 4H2O + 5Fe3+; E°cell = +0.74 V; oxidising agent = Fe2+; reducing agent = MnO4-
Correct Answer
B
Correct Option:
MnO4- + 8H+ + 5Fe2+ -> Mn2+ + 4H2O + 5Fe3+; E°cell = +0.74 V; oxidising agent = MnO4-; reducing agent = Fe2+

About This Question

This is Waec Model Questions Vol1 2018 Chemistry Question 14. It is one of the objective questions from the 2018 Waec Model Questions Vol1 Chemistry examination.

Difficulty level: Medium .

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