UTME 2021 Mathematics | Objective
Practice these randomly selected questions to test your readiness.
Question 1
In how many ways can a delegation of 3 be chosen from 5 men and 3 women, if at least 1 man and 1 woman must be included?
Question 2
If the interest on 3150.00 for \( 2\frac{1}{2} \) years is N4.50, find the interest on N250.00 for 6 months at the same rate.
Question 3
A binary operation \( \otimes \) defined on the set of integers is such that \( m \otimes n = m + n + mn \) for all integers m and n. Find the inverse of -5 under this operation, if the identity element is 0.
Question 4
\( \mathbf{P} \) is a point on one side of the straight line \( \mathbf{U V} \) and \( \mathbf{P} \) moves in the same direction as UV. If the straight line ST is one the locus of P and \( \angle D V U S =50^{\circ} \), find \( \angle D U S T \).
Question 5
What is the size of each interior angle of a 12 -sided regular polygon?
Question 6
Simplify \( 3 \frac{1}{3}-(2\frac{1}{3} \times 1\frac{1}{4})+\frac{3}{5} \)
Question 7
In a right angled triangle, if \( tanq =E \). What is \( \cos q-\sin q \) ?
Question 8
If Q= \( \begin{pmatrix} 9 & -2 \\ -7 & 4\end{pmatrix} \), then |Q| is
Question 9
Find the equation of a line perpendicular to line \( 2 y =5 x+4 \) which passes through (4,2).
Question 10
The sum of the first n terms of the arithmetic progression 5,11,17,23,29,35,... is
Question 11
A chord of a circle of radius 7 cm is 5 cm from the centre of the circle. What is the length of the chord?
Question 12
The perpendicular bisector of a line \( \mathbf{X Y} \) is the locus of a point.
Question 13
A circle of perimeter 28 cm is opened to form a square. What is the maximum possible area of the square?
Question 14
Determine the value of x for which \( (x^{2}-1)>0 \).
Question 15
A man walks \( 100 \text{ m} \) due West from a point X to Y, and then \( 100 \text{ m} \) due North to a point Z. Find the bearing of X from Z.
Master the Exam!
You've seen a preview, but there are thousands more questions plus AI tutor to break down complex solutions.
Unlock Full Access
Available for Android & Windows