POST UTME ACHIEVERS UNIVERSITY 2018 Mathematics | Objective
Practice these randomly selected questions to test your readiness.
Question 1
Find the area under the curve \( y = x^2 \) from \( x = 0 \) to \( x = 4 \).
Question 2
Determine the mean of the following data set: 2, 4, 6, 8, 10. If the mean is increased by 2, what is the new mean?
Question 3
Find the sum of the first 10 terms of the geometric series ( 2, 6, 18, ... )
Question 4
Find the determinant of the matrix \( egin{bmatrix} 2 & 3 \ 4 & 5 \end{bmatrix} \).
Question 5
Find the derivative of the function $f(x) = \ln\( x^2 \)$.
Question 6
Find the area under the curve [ y = x^2 + 2x - 3 ] from x = 0 to x = 4.
Question 7
A random sample of 25 students from a university had a mean height of 175.5 cm with a s\tandard deviation of 5.2 cm. If the population s\tandard deviation is unknown, calculate the 95% confidence interval for the mean height of all students in the university.
Question 8
A rec\tangular prism has a length of 15 cm, a width of 8 cm, and a height of 6 cm. Find the surface area of the prism in square centimeters.
Question 9
Solve the inequality \( 2x^2 + 5x - 3 > 0 \).
Question 10
Solve the quadratic equation \( x^2 + 4x + 4 = 0 \) u\sing the quadratic formula.
Question 11
Solve the matrix equation \( \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \begin{bmatrix} x \ y \end{bmatrix} = \begin{bmatrix} 5 \ 6 \end{bmatrix} \).
Question 12
Find the area under the curve of the function \( f(x) = \frac{1}{x^2 + 1} \) from \( x = 0 \) to \( x = 1 \).
Question 13
A binary operation \( \ast \) on the set \( \{ 1, 2, 3, 4 \} \) is defined as \( a \ast b = a + b \). Find the value of \( 2 \ast 3 \).
Question 14
Solve the quadratic equation \( x^2 + 5x + 6 = 0 \) u\sing the quadratic formula. What is the value of x?
Question 15
A right-angled triangle has a hypotenuse of length 10 cm and one leg of length 6 cm. Find the length of the other leg.
Master the Exam!
You've seen a preview, but there are thousands more questions plus AI tutor to break down complex solutions.
Unlock Full Access
Available for Android & Windows