Neco 2023 Further Mathematics Question 40

Practice objective / multiple choice question 40 from the 2023 Neco Further Mathematics examination.

Neco 2023 Further Mathematics Objective / Multiple Choice Medium Difficulty

Question 40 NECO • 2023 • FURTHER_MATHEMATICS • objective

The circle with centre \(C(2,-1)\) has radius 5. Through the external point \(P(8,3)\) two tangents can be drawn to the circle. Write the equations of both tangent lines in the form \(y = mx + c\).

A. y = \frac{24+15\sqrt{3}}{11}x - \frac{96-120\sqrt{3}}{11} \quad and \quad y = \frac{24-15\sqrt{3}}{11}x - \frac{96+120\sqrt{3}}{11}

B. y = \frac{24+10\sqrt{3}}{11}x - \frac{96+80\sqrt{3}}{11} \quad and \quad y = \frac{24-10\sqrt{3}}{11}x - \frac{96-80\sqrt{3}}{11}

C. y = \frac{30+15\sqrt{3}}{11}x - \frac{120+120\sqrt{3}}{11} \quad and \quad y = \frac{30-15\sqrt{3}}{11}x - \frac{120-120\sqrt{3}}{11}

Correct Answer D. y = \frac{24+15\sqrt{3}}{11}x - \frac{96+120\sqrt{3}}{11} \quad and \quad y = \frac{24-15\sqrt{3}}{11}x - \frac{96-120\sqrt{3}}{11}

Correct Answer

Correct Option:

y = \frac{24+15\sqrt{3}}{11}x - \frac{96+120\sqrt{3}}{11} \quad and \quad y = \frac{24-15\sqrt{3}}{11}x - \frac{96-120\sqrt{3}}{11}

This is Neco 2023 Further Mathematics Question 40. It is one of the objective questions from the 2023 Neco Further Mathematics examination.

Difficulty level: Medium .

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