Neco 2020 Further Mathematics Question 40

Practice objective / multiple choice question 40 from the 2020 Neco Further Mathematics examination.

Neco 2020 Further Mathematics Objective / Multiple Choice Hard Difficulty
Question 40 NECO • 2020 • FURTHER_MATHEMATICS • objective

Consider the system of equations \\n( k+1 )x + 2y - z = 3 \\n2x + ( k-1 ) y + 4z = 5 \\n- x + y + ( k+2 )z = k \\n(a) Determine all real values of \(k\) for which the system has a unique solution. \\n(b) For \(k=1\) solve for \(x, y, z\).

Answer Options

A. Unique when k^{3}+2k^{2}-10k-23 = 0 (approximately k = 3.25); for k=1, (x,y,z) = (1, 1, 1)
Correct Answer B. Unique when k^{3}+2k^{2}-10k-23 \neq 0 (approximately k \neq 3.25); for k=1, (x,y,z) = (13/10, 1/2, 3/5)
C. Unique when k^{3}+2k^{2}-10k-23 \neq 0 (approximately k \neq 2.5); for k=1, (x,y,z) = (5\/4, 2\/3, 1\/2)
D. Unique when k^{2}+2k-23 \neq 0; for k=1, (x,y,z) = (13\/10, 1\/2, 2\/5)
Correct Answer
B
Correct Option:
Unique when k^{3}+2k^{2}-10k-23 \neq 0 (approximately k \neq 3.25); for k=1, (x,y,z) = (13/10, 1/2, 3/5)

About This Question

This is Neco 2020 Further Mathematics Question 40. It is one of the objective questions from the 2020 Neco Further Mathematics examination.

Difficulty level: Hard .

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