Neco 2020 Further Mathematics Question 18

Practice objective / multiple choice question 18 from the 2020 Neco Further Mathematics examination.

Neco 2020 Further Mathematics Objective / Multiple Choice Medium Difficulty
Question 18 NECO • 2020 • FURTHER_MATHEMATICS • objective

A circle has centre \(C(2,-1)\) and radius 5. Through the external point \(P(10,3)\) two tangents can be drawn to the circle. Find the equation of the tangent line with positive gradient and then give the coordinates of its point of tangency.

Answer Options

A. Equation: y-3 = ((32 - 5\sqrt{55})/39)(x-10). Point of tangency: ((1102 - 121\sqrt{55})/(196 + 16\sqrt{55}), -(391 + 94\sqrt{55})/(196 + 16\sqrt{55}))
B. Equation: y-3 = ((32 + 5\sqrt{55})/39)(x+10). Point of tangency: ((1102 + 121\sqrt{55})/(196 + 16\sqrt{55}), (391 + 94\sqrt{55})/(196 + 16\sqrt{55}))
Correct Answer C. Equation: y-3 = ((32 + 5\sqrt{55})/39)(x-10). Point of tangency: ( (1102 + 121\sqrt{55})/(196 + 16\sqrt{55}), -(391 + 94\sqrt{55})/(196 + 16\sqrt{55}) )
D. Equation: y-3 = ((32 + 5\sqrt{55})/39)(x-10). Point of tangency: ((1102 + 121\sqrt{55})/(196 - 16\sqrt{55}), -(391 + 94\sqrt{55})/(196 - 16\sqrt{55}))
Correct Answer
C
Correct Option:
Equation: y-3 = ((32 + 5\sqrt{55})/39)(x-10). Point of tangency: ( (1102 + 121\sqrt{55})/(196 + 16\sqrt{55}), -(391 + 94\sqrt{55})/(196 + 16\sqrt{55}) )

About This Question

This is Neco 2020 Further Mathematics Question 18. It is one of the objective questions from the 2020 Neco Further Mathematics examination.

Difficulty level: Medium .

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