Neco 2019 Further Mathematics Question 37

Practice objective / multiple choice question 37 from the 2019 Neco Further Mathematics examination.

Neco 2019 Further Mathematics Objective / Multiple Choice Medium Difficulty
Question 37 NECO • 2019 • FURTHER_MATHEMATICS • objective

A particle moves along a straight line with displacement \(s(t)=t^{3}-6t^{2}+9t\) metres, where \(t\) is in seconds. (a) Find all times \(t\) in the interval \([0,4]\) at which the instantaneous velocity equals the average velocity over \([0,4]\). (b) Determine the acceleration of the particle at each of those times.

Answer Options

A. Times: \\(t=2\\pm\\frac{2}{3}\\) s; Accelerations: \\(-\\frac{8}{3}\\sqrt{3}\\) m\/s\\(^2\\) and \\(+\\frac{8}{3}\\sqrt{3}\\) m\/s\\(^2\\).
B. Times: \\(t=2\\pm\\frac{3}{\\sqrt{3}}\\) s; Accelerations: \\(-6\\sqrt{3}\\) m\/s\\(^2\\) and \\(+6\\sqrt{3}\\) m\/s\\(^2\\).
C. Times: \\(t=2\\pm\\frac{1}{\\sqrt{3}}\\) s; Accelerations: \\(-2\\sqrt{3}\\) m\/s\\(^2\\) and \\(+2\\sqrt{3}\\) m\/s\\(^2\\).
Correct Answer D. Times: \(t=2\pm\frac{2}{\sqrt{3}}\) s; Accelerations: \(-4\sqrt{3}\) m/s\(^2\) and \(+4\sqrt{3}\) m/s\(^2\).
Correct Answer
D
Correct Option:
Times: \(t=2\pm\frac{2}{\sqrt{3}}\) s; Accelerations: \(-4\sqrt{3}\) m/s\(^2\) and \(+4\sqrt{3}\) m/s\(^2\).

About This Question

This is Neco 2019 Further Mathematics Question 37. It is one of the objective questions from the 2019 Neco Further Mathematics examination.

Difficulty level: Medium .

View More Neco 2019 Further Mathematics Questions More Neco Practice Questions Back to Questions

Master the Exam!

You've seen a preview, but there are thousands more questions plus AI tutor to break down complex solutions.

Unlock Full Access Available for Android & Windows
Chat with Support