Gce Model Questions Vol1 2021 Further Mathematics Question 14

Practice objective / multiple choice question 14 from the 2021 Gce Model Questions Vol1 Further Mathematics examination.

Gce Model Questions Vol1 2021 Further Mathematics Objective / Multiple Choice Hard Difficulty
Question 14 GCE_MODEL_QUESTIONS_VOL1 • 2021 • FURTHER_MATHEMATICS • objective

A particle moves along a straight line with acceleration \(a(t) = -6t + 4\) (in \(\text{m s}^{-2}\)), where \(t\) is in seconds. At \(t = 0\) the particle has velocity \(v(0) = 3\,\text{m s}^{-1}\) and position \(s(0) = 2\,\text{m}\).\n(a) Determine the time (to two decimal places) when the particle comes to rest.\n(b) Find the total distance travelled from \(t = 0\) up to that instant (to two decimal places).

Answer Options

A. t = 1.50 s (to 2 d.p.); distance = 4.80 m (to 2 d.p.)
B. t = 2.13 s (to 2 d.p.); distance = 7.20 m (to 2 d.p.)
Correct Answer C. t = 1.87 s (to 2 d.p.); distance = 6.06 m (to 2 d.p.)
D. t = 2.00 s (to 2 d.p.); distance = 5.50 m (to 2 d.p.)
Correct Answer
C
Correct Option:
t = 1.87 s (to 2 d.p.); distance = 6.06 m (to 2 d.p.)

About This Question

This is Gce Model Questions Vol1 2021 Further Mathematics Question 14. It is one of the objective questions from the 2021 Gce Model Questions Vol1 Further Mathematics examination.

Difficulty level: Hard .

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