Gce Model Questions Vol1 2018 Physics Question 42

Practice objective / multiple choice question 42 from the 2018 Gce Model Questions Vol1 Physics examination.

Gce Model Questions Vol1 2018 Physics Objective / Multiple Choice Hard Difficulty
Question 42 GCE_MODEL_QUESTIONS_VOL1 • 2018 • PHYSICS • objective

An electric circuit consists of a 12.0 V ideal battery, a fixed resistor of 4.0 Ω and a heating coil whose resistance at 20 °C is 2.0 Ω and increases linearly with temperature according to \(R_{\text{coil}} = 2.0\,[1+\alpha (T-20^{\circ}\text{C})]\) where \(\alpha = 4.0\times10^{-3}\,\text{°C}^{-1}\). The coil loses heat to water at a rate of 10.0 W per degree Celsius rise of the coil above the ambient temperature (20 °C). In steady state the electrical power dissipated in the coil equals the rate of heat loss. Determine (a) the current flowing in the circuit and (b) the temperature rise \(\Delta T\) of the coil above 20 °C.

Answer Options

A. I ≈ 2.50 A, ΔT ≈ 0.50 °C
Correct Answer B. I ≈ 2.00 A, ΔT ≈ 0.80 °C
C. I ≈ 1.80 A, ΔT ≈ 0.95 °C
D. I ≈ 1.50 A, ΔT ≈ 1.20 °C
Correct Answer
B
Correct Option:
I ≈ 2.00 A, ΔT ≈ 0.80 °C

About This Question

This is Gce Model Questions Vol1 2018 Physics Question 42. It is one of the objective questions from the 2018 Gce Model Questions Vol1 Physics examination.

Difficulty level: Hard .

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