City Guilds Model Questions Vol1 2025 Engineering Question 48

Practice objective / multiple choice question 48 from the 2025 City Guilds Model Questions Vol1 Engineering examination.

City Guilds Model Questions Vol1 2025 Engineering Objective / Multiple Choice Hard Difficulty
Question 48 CITY_GUILDS_MODEL_QUESTIONS_VOL1 • 2025 • ENGINEERING • objective

In a turning operation the workpiece diameter is \(100\) mm. The depth of cut is \(2\) mm and the feed is \(0.2\) mm per revolution. Tool life follows Taylor's equation \( T = \dfrac{C}{V^{n}} \) with \( C = 2000\; \text{min·(m/min)}^{n} \) and \( n = 0.25 \). The power required is approximated by \( P = k V^{2} \) where \( k = 0.0005\; \text{kW·(m/min)}^{-2} \). The electricity cost is ₦0.5 per kWh and the tool cost is ₦2000. Assuming the spindle speed is related to cutting speed by \( N = \dfrac{V}{\pi D} \) (with \( D = 0.1\) m), determine the cutting speed \( V \) (in m min\(^{-1}\)) between \(50\) m min\(^{-1}\) and \(250\) m min\(^{-1}\) that minimises the total cost per part (tool cost plus energy cost). Also give the minimum cost per part in naira, rounded to three decimal places.

Answer Options

Correct Answer A. Optimal speed = 50 m/min; Minimum cost ≈ 0.033 ₦ per part
B. Optimal speed = 200 m/min; Minimum cost ≈ 0.060 ₦ per part
C. Optimal speed = 120 m/min; Minimum cost ≈ 0.045 ₦ per part
D. Optimal speed = 80 m/min; Minimum cost ≈ 0.038 ₦ per part
Correct Answer
A
Correct Option:
Optimal speed = 50 m/min; Minimum cost ≈ 0.033 ₦ per part

About This Question

This is City Guilds Model Questions Vol1 2025 Engineering Question 48. It is one of the objective questions from the 2025 City Guilds Model Questions Vol1 Engineering examination.

Difficulty level: Hard .

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