City Guilds Model Questions Vol1 2023 Information Technology Question 18

Practice objective / multiple choice question 18 from the 2023 City Guilds Model Questions Vol1 Information Technology examination.

City Guilds Model Questions Vol1 2023 Information Technology Objective / Multiple Choice Easy Difficulty
Question 18 CITY_GUILDS_MODEL_QUESTIONS_VOL1 • 2023 • INFORMATION_TECHNOLOGY • objective

Four processes have CPU burst times (in milliseconds) as follows: P1 = 6 ms, P2 = 8 ms, P3 = 7 ms, P4 = 3 ms. Compute the average waiting time for (a) First‑Come‑First‑Served (FCFS) and (b) non‑preemptive Shortest‑Job‑First (SJF). Which algorithm yields the lower average waiting time?

Answer Options

A. FCFS average waiting time = 11 ms; SJF average waiting time = 7 ms; FCFS is lower
B. FCFS average waiting time = 9.75 ms; SJF average waiting time = 8 ms; SJF is lower
C. FCFS average waiting time = 10.25 ms; SJF average waiting time = 6 ms; SJF is lower
Correct Answer D. FCFS average waiting time = 10.25 ms; SJF average waiting time = 7 ms; SJF is lower
Correct Answer
D
Correct Option:
FCFS average waiting time = 10.25 ms; SJF average waiting time = 7 ms; SJF is lower

About This Question

This is City Guilds Model Questions Vol1 2023 Information Technology Question 18. It is one of the objective questions from the 2023 City Guilds Model Questions Vol1 Information Technology examination.

Difficulty level: Easy .

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