Utme 2021 Chemistry Question 8

Practice objective / multiple choice question 8 from the 2021 Utme Chemistry examination. This question covers Chemical reactions, Stoichiometry .

Utme 2021 Chemistry Objective / Multiple Choice 2 Difficulty
Topics: Chemical reactions Stoichiometry
Question 8 UTME • 2021 • CHEMISTRY • objective

The number of molecules of carbon(IV) oxide produced when 10.0 g of CaCO3 is treated with \( 0.2 dm^3 \) of 1 M HCl in the equation \( \mathrm{CaCO}_3 + 2 \mathrm{HCl} \rightarrow \mathrm{CaCl}_2 + \mathrm{H}_2O + \mathrm{CO}_2 \text{ is }\) \([ \mathrm{Ca} \text{= 40.0}, \mathrm{H} \text{= 1}, \mathrm{Cl} \text{= 35.5} ] \)

Answer Options

Correct Answer A. \( 1.00 \times 10^{23} \)
B. \( 6.02 \times 10^{23} \)
C. \( 6.02 \times 10^{n} \)
D. \( 6.02 \times 10^{n} \)
Correct Answer
A
Correct Option:
\( 1.00 \times 10^{23} \)

About This Question

This is Utme 2021 Chemistry Question 8. It is one of the objective questions from the 2021 Utme Chemistry examination.

The question covers Chemical reactions, Stoichiometry .

Difficulty level: 2 .

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