Post Utme Veritas University 2025 Mathematics Question 1

Practice objective / multiple choice question 1 from the 2025 Post Utme Veritas University Mathematics examination.

Post Utme Veritas University 2025 Mathematics Objective / Multiple Choice
Question 1 POST_UTME_VERITAS_UNIVERSITY • 2025 • MATHEMATICS • objective
Post Utme Veritas University 2025 Mathematics Question 1 diagram

In the diagram below, the equation of the circle is given by \(x - h \\)^2 + \(y - k\)^\(2 = r\^2\) ). If the center of the circle is at ( (h,\(k) = (2\), 3) ) and the radius is 4, find the equation of the circle.

Answer Options

Correct Answer A. \(x - 2 \\)^2 + \(y - 3\)^\(2 = 16\) )
B. \(x - 2 \\)^2 + \(y - 3\)^\(2 = 25\) )
C. \(x - 2 \\)^2 + \(y - 3\)^\(2 = 36\) )
D. \(x - 2 \\)^2 + \(y - 3\)^\(2 = 49\) )
Correct Answer
A
Correct Option:
\(x - 2 \\)^2 + \(y - 3\)^\(2 = 16\) )

About This Question

This is Post Utme Veritas University 2025 Mathematics Question 1. It is one of the objective questions from the 2025 Post Utme Veritas University Mathematics examination.

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