Post Utme Veritas University 2025 Chemistry Question 8

Practice objective / multiple choice question 8 from the 2025 Post Utme Veritas University Chemistry examination.

Post Utme Veritas University 2025 Chemistry Objective / Multiple Choice

Question 8 POST_UTME_VERITAS_UNIVERSITY • 2025 • CHEMISTRY • objective

The solubility of a sparingly soluble salt is given by the equation: S = Ksp / [A]^x [B]^y. If the solubility product cons\tant (Ksp) of a salt is 1.0 × 10^\( -5 \) and the concentrations of the ions are [A] = 0.1 M and [B] = 0.01 M, what is the solubility of the salt?

Answer Options

Correct Answer A. 1.0 × 10^\( -4 \) M

B. 1.0 × 10^\( -3 \) M

C. 1.0 × 10^\( -2 \) M

D. 1.0 × 10^\( -1 \) M

Correct Answer

Correct Option:

1.0 × 10^\( -4 \) M

About This Question

This is Post Utme Veritas University 2025 Chemistry Question 8. It is one of the objective questions from the 2025 Post Utme Veritas University Chemistry examination.

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