Post Utme Veritas University 2021 Mathematics Question 3

Practice objective / multiple choice question 3 from the 2021 Post Utme Veritas University Mathematics examination.

Post Utme Veritas University 2021 Mathematics Objective / Multiple Choice
Question 3 POST_UTME_VERITAS_UNIVERSITY • 2021 • MATHEMATICS • objective
Post Utme Veritas University 2021 Mathematics Question 3 diagram

A circle has an equation of the form \(x - h \\)^2 + \(y - k\)^\(2 = r\^2\) ). If the center of the circle is at (3, 4) and the radius is 5, find the equation of the circle.

Answer Options

Correct Answer A. \(x - 3\)^2 + \(y - 4\)^\(2 = 25\)
B. \(x - 4\)^2 + \(y - 3\)^\(2 = 25\)
C. \(x - 3\)^2 + \(y - 4\)^\(2 = 9\)
D. \(x - 4\)^2 + \(y - 3\)^\(2 = 9\)
Correct Answer
A
Correct Option:
\(x - 3\)^2 + \(y - 4\)^\(2 = 25\)

About This Question

This is Post Utme Veritas University 2021 Mathematics Question 3. It is one of the objective questions from the 2021 Post Utme Veritas University Mathematics examination.

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