Post Utme Veritas University 2021 Mathematics Question 15

Practice objective / multiple choice question 15 from the 2021 Post Utme Veritas University Mathematics examination.

Post Utme Veritas University 2021 Mathematics Objective / Multiple Choice
Question 15 POST_UTME_VERITAS_UNIVERSITY • 2021 • MATHEMATICS • objective

Solve the trigonometric equation \(\sin^2 x + \cos^2 x = 1\) for ( x ) in the interval ( [0, 2pi] ).

Answer Options

Correct Answer A. [0, \(\frac{\pi}{2}\)\), \pi, \(\frac{3\pi}{2}\)\)]
B. [0, \pi, 2pi]
C. [\(\frac{\pi}{2}\)\), \pi, \(\frac{3\pi}{2}\)\)]
D. [0, \(\frac{\pi}{4}\)\), \(\frac{3\pi}{4}\)\)]
Correct Answer
A
Correct Option:
[0, \(\frac{\pi}{2}\)\), \pi, \(\frac{3\pi}{2}\)\)]

About This Question

This is Post Utme Veritas University 2021 Mathematics Question 15. It is one of the objective questions from the 2021 Post Utme Veritas University Mathematics examination.

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