Post Utme Veritas University 2019 Mathematics Question 24

Practice objective / multiple choice question 24 from the 2019 Post Utme Veritas University Mathematics examination.

Post Utme Veritas University 2019 Mathematics Objective / Multiple Choice
Question 24 POST_UTME_VERITAS_UNIVERSITY • 2019 • MATHEMATICS • objective

Find the equation of the circle with center \(C -2, 3 \\) ) and radius \(r = 4\).

Answer Options

Correct Answer A. \(x + 2\)^2 + \(y - 3\)^\(2 = 16\)
B. \(x - 2\)^2 + \(y + 3\)^\(2 = 16\)
C. \(x + 2\)^2 + \(y + 3\)^\(2 = 16\)
D. \(x - 2\)^2 + \(y - 3\)^\(2 = 16\)
Correct Answer
A
Correct Option:
\(x + 2\)^2 + \(y - 3\)^\(2 = 16\)

About This Question

This is Post Utme Veritas University 2019 Mathematics Question 24. It is one of the objective questions from the 2019 Post Utme Veritas University Mathematics examination.

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