A particle of mass $m$ is moving in a circular orbit of radius $r$ in a potential $V(r) = \frac{k}{r}$. If the particle's angular momentum is $L = 2 mu r^2 omega$, where $mu$ is the reduced mass and $omega$ is the angular frequency, find the total energy $E$ of the particle.

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E = \frac{1}{2} m r^2 \omega^2 - \frac{k}{r}

Post Utme Unilorin 2022 Physics Question 36

A particle of mass $m$ is moving in a circular orbit of radius $r$ in a potential $V(r) = \frac{k}{r}$. If the particle's angular momentum is $L = 2 mu r^2 omega$, where $mu$ is the reduced mass and $omega$ is the angular frequency, find the total energy $E$ of the particle.

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